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How to check if a set is a proper subset of another set in Ruby
okwudili onyejiaku
Overview
A set is a collection of values that are unique but unordered. A set B is a proper subset of a set A if all the elements or values of B are present in A , while A also contains one or more elements that are not present in B.
To check if a set is a proper subset of another set, we can use the proper_subset() method in Ruby.
Syntax
set1.proper_subset(set2)
Syntax for proper_subset() in Ruby
Parameters
set1: This is the set we are checking to see if it is a proper subset of another set.
set2: This is the set to which we are comparingset1.
Return value
The returned value is a boolean value. We get true if set1 is a proper subset of set2. Otherwise, we get a false.
Code
# require the set class
require "set"
# create some sets
EvenNumbers = Set.new([2, 4, 6, 8, 10])
NumbersToTen = Set.new([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])
Names = Set.new(["Amaka", "Titi"])
Workers = Set.new(["Amaka", "Chioma", "Titi"])
EmptySet = Set.new([])
Alphabets = Set.new(["a", "b", "c", "d", "e", "f", "g",
"h", "i", "j", "k", "l", "m", "n", "o", "p", "q",
"r", "s", "t", "u", "v", "w", "x", "y", "z"
])
Vowels = Set.new(["a", "e", "i", "o", "u"])
# check if proper subsets exists
puts NumbersToTen.proper_subset?(EvenNumbers) # false
puts Names.proper_subset?(Workers) # true
puts EmptySet.proper_subset?(Names) # true
puts Alphabets.proper_subset?(Vowels) # falseCheck if a set is a proper subset of another
Explanation
- Line 2: We require the set class.
- Lines 5–14: We create some sets.
- Lines 17–20: We use the
proper_subset?()method to check whether any proper subsets exist among the created sets. Then we print the results to the console.
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okwudili onyejiaku
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