Solution: Circular Array Loop

Explore how to detect cycles in circular arrays using the fast and slow pointers method. Understand how moving pointers at different speeds helps identify loops where all steps go in one direction. This lesson guides you through implementing an efficient solution to the Circular Array Loop problem, highlighting time and space complexity tradeoffs.

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Statement
Solution
- Naive approach
- Optimized approach using fast and slow pointers

Statement

There is a circular list of non-zero integers called nums. Each number in the list tells you how many steps to move forward or backward from your current position:

If nums[i] is positive, move nums[i] steps forward.
If nums[i] is negative, move nums[i] steps backward.

As the list is circular:

Moving forward from the last element takes you back to the first element.
Moving backward from the first element takes you to the last element.

A cycle in this list means:

You keep moving according to the numbers, and you end up repeating a sequence of indexes.
All numbers in the cycle have the same sign (either all positive or all negative).
The cycle length is greater than 1 (it involves at least two indexes).

Return true if such a cycle exists in the list or false otherwise.