Given a positive integer n, create an $n \times n$, matrix where the elements are sequential integers from $1$ to $n^2$, arranged in a spiral pattern.

Constraints:

• 1 $\leq$n $\leq$$20$

The essence of this solution lies in systematically filling an $n×n$ matrix in a spiral order by iterating layer by layer. The core idea is to divide the matrix into layers and traverse each layer in four directional steps (right, down, left, and up), filling the matrix cells with sequential numbers. This approach ensures the matrix is filled in a spiral pattern.

Now, let’s look at the steps of the solution:

1. We initialize a matrix of size $n×n$ ...