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Solution: Jewels and Stones

Understand how to count jewels within a collection of stones by leveraging hash maps for efficient membership checking. This lesson teaches you to implement a case-sensitive solution that scans stones while checking against a jewel set, optimizing both time and space complexity for coding interviews.

Statement

You are given two strings, jewels and stones. Each character in jewels represents a stone type that is a jewel, and each character in stones represents a stone you have. Count how many characters in stones belong to the set of characters in jewels.

Note: Matching is case-sensitive, so 'a' and 'A' are different types of stones.

Constraints:

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