You are given a list of words, where each string has the same length target, of length target can be formed using the given words under the following rules:
You must build the target from left to right.
To form the ith character (0-indexed) of target, you can choose any kth character of any jth string in words, i.e., target[i] = words[j][k].
Once you use the kth character of the jth string in words, your next letter can't be a character from index k of any string in words. In simple words, all characters to the left of or at index k become unusable for every string, and the next letter must come from positions strictly to the right of k.
Repeat the process until you’ve formed the complete target.
Note: You can use multiple characters from the same string in
words, as long as the rules above are followed.
Your task is to find and return the number of ways to form the string target from words. As the answer might be too large, return it modulo
Constraints:
words.length
words[i].length
All strings in words have the same length.
target.length
words[i] and target contain only lowercase English letters.
As all words have the same length, placing them one under another creates a word grid where each column contains characters from the same position in each word. This helps to quickly find how many times a certain character appears at a specific position across all words.
In this solution, the first step is to go through the character grid and count how many times each character appears in every column. We store these counts in a frequency table, a 2D list where each row represents a column in the words, and each entry keeps track of how many times a character shows up there. This saves us time later because we don’t have to scan all the words repeatedly.
The next step is to calculate how many ways we can form the target string by gradually building it, using ...
You are given a list of words, where each string has the same length target, of length target can be formed using the given words under the following rules:
You must build the target from left to right.
To form the ith character (0-indexed) of target, you can choose any kth character of any jth string in words, i.e., target[i] = words[j][k].
Once you use the kth character of the jth string in words, your next letter can't be a character from index k of any string in words. In simple words, all characters to the left of or at index k become unusable for every string, and the next letter must come from positions strictly to the right of k.
Repeat the process until you’ve formed the complete target.
Note: You can use multiple characters from the same string in
words, as long as the rules above are followed.
Your task is to find and return the number of ways to form the string target from words. As the answer might be too large, return it modulo
Constraints:
words.length
words[i].length
All strings in words have the same length.
target.length
words[i] and target contain only lowercase English letters.
As all words have the same length, placing them one under another creates a word grid where each column contains characters from the same position in each word. This helps to quickly find how many times a certain character appears at a specific position across all words.
In this solution, the first step is to go through the character grid and count how many times each character appears in every column. We store these counts in a frequency table, a 2D list where each row represents a column in the words, and each entry keeps track of how many times a character shows up there. This saves us time later because we don’t have to scan all the words repeatedly.
The next step is to calculate how many ways we can form the target string by gradually building it, using ...