Solution: Word Break

Explore dynamic programming techniques to solve the Word Break problem by determining if a string can be segmented into valid dictionary words. Understand the drawbacks of naive recursive approaches and implement a lookup table method to optimize performance. This lesson helps you analyze time and space complexities while applying pointers and substring checks for an efficient solution.

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Statement
Solution
- Naive approach
- Optimized approach using dynamic programming

Statement

Given a string, s, and a dictionary of strings, word_dict, check if s can be segmented into a space-separated sequence of one or more dictionary words. If yes, return TRUE; else, return FALSE.

Note: The same word in the dictionary may be used multiple times.

Constraints:

$1 \leq$ s.length $\leq 250$
$1 \leq$ word_dict.length $\leq 1000$
$1 \leq$ word_dict[i].length $\leq 20$
s and word_dict[i] consist of only lowercase English letters.
All the strings of word_dict are unique.

Solution

So far, you’ve probably brainstormed some approaches and have an idea of how to solve this problem. Let’s explore some of these approaches and figure out which one to ...