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Problem: Loud and Rich

Medium
30 min
Explore how to identify the quietest person who is richer or equally rich for each individual using algorithmic patterns. This lesson guides you through efficient problem-solving strategies and coding practice to master this classic challenge.

Statement

You’re given a group of individuals where everyone has a specific amount of money and a different level of quietness. Additionally, you’re given an array richer = [xi,yi][x_{i}, y_{i}​], so that xix_{i}​ has more money than yiy_{i}​. The quietness level of each individual is represented using an array named quiet.

Return an integer array res, where res[i] = y. If y has the lowest value in quiet[y] among all individuals, who have equal or more money than the individual i.

Constraints:

  • n=n = quiet.length
  • 11 \leq nn 500\leq 500
  • 00 \leq quiet[i] << nn
  • All the values of quiet are unique.
  • 00 \leq richer.length n(n1)/2\leq n * (n - 1) / 2
  • 00 \leq x[i], y[i] << n
  • xix_{i} !=!= yiy_{i}
  • All the pairs of richer are unique.
  • The observations in richer are all logically consistent.
Problem
Ask
Submissions

Problem: Loud and Rich

Medium
30 min
Explore how to identify the quietest person who is richer or equally rich for each individual using algorithmic patterns. This lesson guides you through efficient problem-solving strategies and coding practice to master this classic challenge.

Statement

You’re given a group of individuals where everyone has a specific amount of money and a different level of quietness. Additionally, you’re given an array richer = [xi,yi][x_{i}, y_{i}​], so that xix_{i}​ has more money than yiy_{i}​. The quietness level of each individual is represented using an array named quiet.

Return an integer array res, where res[i] = y. If y has the lowest value in quiet[y] among all individuals, who have equal or more money than the individual i.

Constraints:

  • n=n = quiet.length
  • 11 \leq nn 500\leq 500
  • 00 \leq quiet[i] << nn
  • All the values of quiet are unique.
  • 00 \leq richer.length n(n1)/2\leq n * (n - 1) / 2
  • 00 \leq x[i], y[i] << n
  • xix_{i} !=!= yiy_{i}
  • All the pairs of richer are unique.
  • The observations in richer are all logically consistent.