Apply your skills to use stacks for various tasks, including calculators, string manipulation, and queuing.

Central CIP Path

Stacks


# Statement

Given a string, `s`, that may have #key# matched: Each opening parenthesis, (, has a closing parenthesis, ), for it. #key# and #key# unmatched: There is no corresponding closing parenthesis, ), for an opening parenthesis, (. #key# parentheses, remove the minimum number of parentheses so that the resulting string represents a valid parenthesization. For example, the string "a(b)" represents a valid parenthesization while the string "a(b" doesn't, since the opening parenthesis doesn't have any corresponding closing parenthesis.

**Constraints:**

* $1 \leq$ `s.length` $\leq 10^3$
* `s[i]` is either an opening parenthesis $($ , a closing parenthesiss $)$, or a lowercase English letter.

Let's solve the Minimum Remove to Make Valid Parentheses problem using the Stacks pattern.

Solution: Minimum Remove to Make Valid Parentheses

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Solution: Minimum Remove to Make Valid Parentheses

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