Solution: Optimal Account Balancing

Statement▼

Given a list of transactions, where each transaction is represented as $transactions[i] = [from_i,~ to_i,~amount_i]$ , indicating that the person $from_i$ gave $amount_i$ to the person $to_i$ . Return the minimum number of transactions needed to settle all debts.

Constraints:

$1\leq$ transactions.length $\leq10$
transactions[i].length $==3$
$0 \leq$ from_i, to_i $\leq10$
$1\leq$ amount_i $\leq100$
from_i $\neq$ to_i

This solution calculates the minimum number of transactions required to settle debts among a group of people based on an initial set of transactions. It begins by computing each person’s net balance, indicating how much they owe or are owed. Any individuals with a zero net balance are ignored, as they have no outstanding debts or credits.

Once the net balances are calculated, the algorithm uses a recursive approach to settle the remaining balances. It pairs individuals with opposite balances (i.e., those who owe with those who are owed) to reduce them to zero with the minimum number of transactions. The solution explores various pairings and tracks each combination’s cost (number of transactions), ensuring optimal results. If a particular path doesn’t minimize the transactions, it backtracks to explore alternative pairings.

Here’s the step-by-step implementation of the solution:

For each transaction, decrease the balance of the person who gave the money and increase the balance of the person who received it.
Ignore people with a zero balance after all transactions, as they neither owe nor are owed.
Use depth-first search (DFS) to recursively calculate the minimum number of transactions required to settle all balances.
- Base case: If the current person reaches $n$ (number of people with non-zero balances), meaning all balances are zero or settled, return $0$ .
- For each next person:
  - If the current and next person have opposite sign balance:
    - Temporarily add the current person’s balance to the next person’s balance.
    - Recursively call DFS with the next person’s index.
    - Track the minimum of the existing cost and the new cost calculated by DFS.
    - Backtrack: Restore the balance to its original state by reversing the temporary addition.
- Return the minimum cost for all possible transaction paths.

Let’s look at the following illustration to get a better understanding of the solution:

Problem

Submissions

Solution: Optimal Account Balancing

Statement▼

Constraints:

$1\leq$ transactions.length $\leq10$
transactions[i].length $==3$
$0 \leq$ from_i, to_i $\leq10$
$1\leq$ amount_i $\leq100$
from_i $\neq$ to_i

Here’s the step-by-step implementation of the solution:

For each transaction, decrease the balance of the person who gave the money and increase the balance of the person who received it.
Ignore people with a zero balance after all transactions, as they neither owe nor are owed.
Use depth-first search (DFS) to recursively calculate the minimum number of transactions required to settle all balances.
- Base case: If the current person reaches $n$ (number of people with non-zero balances), meaning all balances are zero or settled, return $0$ .
- For each next person:
  - If the current and next person have opposite sign balance:
    - Temporarily add the current person’s balance to the next person’s balance.
    - Recursively call DFS with the next person’s index.
    - Track the minimum of the existing cost and the new cost calculated by DFS.
    - Backtrack: Restore the balance to its original state by reversing the temporary addition.
- Return the minimum cost for all possible transaction paths.

Let’s look at the following illustration to get a better understanding of the solution: