Write a program that prints numbers from 1 to 100
, and:
3
, print Fizz
instead of the number.5
, print Buzz
.3
and 5
, print FizzBuzz
.number
.1,2,3,4,5... 100
1, 2, Fizz
, 4, Buzz
, Fizz
, 7, 8, Fizz
, Buzz
, 11, Fizz
, 13, 14,
FizzBuzz
…
1
and 2
are not multiples of either 3
or 5
, so we print the same number.
3
is a multiple of 3
, so we print Fizz
.
5
is a multiple of 5
, so we print Buzz
.
6
is a multiple of 3
, so we print Fizz
.
7
and 8
are not multiples of either 3
or 5
, so we print the same number.
9
is a multiple of 3
, so we print Fizz
.
10
is a multiple of 5
, so we print Fizz
.
11
is not a multiple of either 3
or 5
, so we print the same number.
12
is a multiple of 3
, so we print Fizz
.
13
and 14
are not multiples of either 3
or 5
, so we print the same number.
15
is a multiple of both 3
and 5
, so we print FizzBuzz
.
We will use a for-in-range
loop to solve this problem.
In the code snippet below, we use a for-in-range
loop to traverse numbers from 1
to 100
.
Note that we use
101
; the loop won’t include last element, so it goes up to100
.
Use if-elif-else
to check if the number is divisible by 3
or 5
or both.
3
nor 5
, then print the same number.#for loop that traverses numbers from 1 to 100 for i in range(1,101): #check if number is divisible by both 3 and 5 if(i%3==0 and i%5==0): print("FizzBuzz") #check if number is divisible by 3 elif(i%3 == 0): print("Fizz") #check if number is divisible by 5 elif(i%5 == 0): print("Buzz") #if not divisible by either of them print the i else: print(i)
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