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In JavaScript, automatic type conversion occurs as needed. Comparison operators take two numerical operands. If one of the operands is not of numerical type, it gets converted to a numerical before applying the operation.

Type conversion doesn’t work for all operators.

```
x < y < z
```

5 < 10 < 15

Let’s take the values above and see what happens.

- In this comparison,
`(x < y < z)`

is equivalent to`((x<y)<z)`

. - As both operators are
`<`

, they have the same precedence. However, since`<`

has left associativity, the expression is evaluated from left to right. Therefore,`5 < 10`

is executed first, and returns`true`

. - Next to be executed is
`true < 15`

. As discussed earlier, type conversion happens, and`true`

is converted to`1`

. - The effective expression is now
`1 < 15`

, which returns`true`

.

15 > 10 > 5

Let’s take the values above and see what happens.

- In this comparison,
`(x > y > z)`

is equivalent to`((x>y)>z)`

. - As both operators are
`>`

, they have the same precedence. However, since`>`

has left associativity, the expression is evaluated from left to right. Therefore,`15 > 10`

is executed first and returns`true`

. - Next to be executed is
`true > 5`

. As discussed earlier, type conversion happens and`true`

is converted to`1`

. - The effective expression is now
`1 > 5`

, which returns`false`

.

// Example 1 x = 5 < 10 console.log("5 < 10 is " + x) console.log(x + " < 15 is " + (x < 15)) // Example 2 y = 15 > 10 console.log("15 > 10 is " + y) console.log(y + " > 5 is " + (y > 5))

These cases can also be solved using logical operators.

**Multiple comparison operators** are more complex to understand and do not improve the readability of the code. On the other hand, **logical operators** (AND, OR, NOT) provide more readability and are easy to understand.

Therefore, multiple comparison operators should be avoided by using the AND and OR operators to split the expression.

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javascript

comparison

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