# Overview

The **sum of the squares** of the first n natural numbers involves calculating the sum of squares from 1 to n. 

Mathematically, the formula for the sum of squares of the first n natural numbers is given as follows: 

$\sum_{i=1}^n$ $i^{2}$ = $1^{2}$ + $2^{2}$ + $3^{2}$ + $4^{2}$ + ... + $n^{2}$

In this shot, we will write a simple program that calculates the sum of the squares of the first n natural numbers.

# Code

We will solve this problem using the `while` and `for` loops.

## Method 1: `while` loop

The following code calculates the sum of the first n natural numbers using the `while` loop:

#include<iostream>
using namespace std;

int main() {
  int sum = 0, i = 1, n = 5;
  
  // iterating i from 1 to n
  while (i <= n) 
  {
    // finding square of i and adding to sum
    sum += i * i;
    i++;
  }

  // displaying the final result
  cout << "The sum of squares of first " << n << " numbers is: " << sum << endl;
  return 0;
}

## Explanation

The `while` loop provides a condition that while ``i`` is less than ``n``, the program will calculate the sum of squares using an increment for the squares sequentially. So it provides an increment in *line 10* and also an increment of the numbers (preceding the value of n) by one in *line 11*.

## Method 2: `for` loop

The following code calculates the sum of the first n natural numbers using a `for` loop:

#include<iostream>
using namespace std;

int main() {
  int sum = 0, n = 5;
  
  // iterating i from 1 to n
  for (int i = 1; i <= n; i++)
  {
    // finding square of i and adding to sum
    sum += i * i;
  }

  // displaying the final result
  cout << "The sum of squares of first " << n << " numbers is: " << sum << endl;
  return 0;
}

This is how we can successfully create a program to compute the sum of squares of the first n natural numbers with a `for` loop.

How to calculate the sum of squares of the first n numbers in C++

Overview The sum of the squares of the first n natural numbers involves calculating the sum of squares from 1 to n. Mathematically, the formula for the sum of squares of the first n natural numbers is given as follows: ∑i=1n\sum_{i=1}^n∑i=1n​ i2i^{2}i2 = 121^{2}12 + 222^{2}22 + 323^{2}32 + 424^{2}42 + … + n2n^{2}n2 In this shot, we will write a simple program that calculates the sum of the squares of the first n natural numbers. Code We will solve this problem using the while and for loops. Method 1: while loop The following code calculates the sum of the first n natural numbers using the while loop: 

How to calculate the sum of squares of the first n numbers in C++

Overview

Code

Method 1: while loop

Explanation

Method 2: for loop

Method 1: `while` loop

Method 2: `for` loop