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MUPPIDI BHAVANA

Any positive integer of length *n* is considered an **Armstrong number** if the number equals the sum of each of its digits raised to the power *n*. The following equation captures this condition:

Where

For example,

The below Python code demonstrates how to determine if a number is an Armstrong number.

length_n = len(n) original_n = int(n) for i in n: list.append(int(i)**length_n) sum_n = sum(list) if sum_n == original_n: print(n, "is an Armstrong number") else: print(n, "is not an Armstrong number")

Enter the input below

Enter your input and hit run! This code determines if a number is an Armstrong number

The code assumes that a number has been inputted and stored in `n`

.

- Line 1: We calculate the length of
`n`

using`len()`

and store it in`length_n`

. - Line 2: We cast
`n`

as`int`

and store it in`original_n`

. - Lines 3–6: We use a
`for`

loop to store cubes of each of the digits of`n`

in`list`

. Next, we add all the elements of`list`

and store the result in`sum_n`

. - Lines 8–9: We print the output that suggests if
`n`

is an Armstrong number, that is if the sum of each of its digits’ cube equals`n`

itself.

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