Let's say that the `double` variable `x` holds the value 3.6987 and needs to be converted to an `int`. There are two ways that this can be done:

- All the digits after the decimal are lost and `x` holds the integer $3$; this can be done using *typecasting* in Java.

- The value is rounded off to the nearest integer (i.e.,3.6987 is rounded off to $4$); this can be done using the `Math.round()` function in Java.​

# 1. Typecasting

Since `double` is a bigger data type than `int`, it needs to be down-casted. See the syntax below:

```
int IntValue = (int) DoubleValue;
```
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# Code

The code snippet below illustrates `double` to `int` typecasting in Java:

class DoubleToInt {
    public static void main( String args[] ) {
        double DoubleValue = 3.6987;
        int IntValue = (int) DoubleValue;
        System.out.println(DoubleValue + " is now " + IntValue);
    }
}

# 2. Using `Math.round()`

`Math.round()` accepts a `double` value and converts it into the nearest `long` value by adding $0.5$ to the value and truncating its decimal points. The `long` value can then be converted to an `int` using typecasting.

The syntax for the `Math.round()` function is:

```
long Math.round(double DoubleValue);
```

<br>

The code snippet below illustrates the usage of `Math.round()` when converting a `double` data type to an `int` in Java:

class DoubleToInt {
    public static void main( String args[] ) {
        double DoubleValue = 3.6987;
        int IntValue = (int) Math.round(DoubleValue);
        System.out.println(DoubleValue + " is now " + IntValue);
    }
}

How to convert  a double to int in Java

Convert a double to int in Java using typecasting for truncation or Math.round() for rounding.

How to convert a double to int in Java

1. Typecasting

Code

2. Using Math.round()

2. Using `Math.round()`