
Decoding a binary string in JavaScript is not a straightforward task because there is no general method for it.

But don't fret. We can code our own solution for this problem. 

Here's to show how to decode a binary string in JavaScript with simple steps.


## Decode a binary string 

Below are simple steps to follow to decode a binary string in JavaScript:

- **Step 1:** Split the binary into an array of strings using the `.split()` method. 

- **Step 2:** Iterate over the elements of the new array created to change each element to a decimal. We can do this by using the `.map()` method. 

> **Note:** We change the elements to decimal to make it easier to convert them to text later. This is because whole numbers can't be changed to text in JavaScript. 

- **Step 3:** Use `String.fromCharCode` with `.map()` to change each element of the array to text. 

- **Step 4:** Add the new array elements together to create a string. This can be done with the `.join()` method.

- **Step 5:** Return the new string.

Below is an example:


function decodeBinary(binary){

// Step 1 
// Split the binary into an array of strings using the .split() method
binary = binary.split(' ');

// Step 2
// Iterate over the elements of the new array create to change each element to a decimal
binary = binary.map(elem => parseInt(elem,2));

// Step 3
// Use String.fromCharCode with .map() to change each element of the array to text 
binary = binary.map(elem => String.fromCharCode(elem));

// Step 4
// Add the element of the new array together to create a string. Save it to a new Variable.
let newText = binary.join("").toUpperCase();

// Step 5 
// The new string is returned
return newText;
}

console.log(decodeBinary("01000011, 01001111, 01000100, 01101001, 01101110, 01000111, 001000002, 01101001, 01110011, 001000002, 01000110, 01010101, 01001110"));

codemirror

console

This is a simple method to decode a binary string. 

How to decode a binary string in JavaScript

Split the binary string, convert to decimals, map to characters with `String.fromCharCode`, join, and return.