In this shot, we will discuss how to display numbers in reverse order in C++.

# Approach
We will use a loop to print numbers in reverse order.

Let's look at the image below to understand it better.


In the image above, we can see that the number was initially written from left to right, but it is written from right to left when we reverse the number. 

We will do the same. We can use the `for` loop to generate code to reverse a number in C++.

# Code

Let's look at the following code snippet to understand it better. 

#include <iostream>
using namespace std;

int main() {
  int number, remainder, sum = 0;
  cin >> number;
  for (int i = number; number != 0; number = number/10)
  {
    remainder = number % 10;
    sum = sum * 10 + remainder;
  }
  cout << "The number in reverse order is: " << sum << endl;
  return 0;
}

*(Enter a number above to generate output)*
# Explanation
* *In line 5,* we initialize the `number`, `remainder`, and `sum` variables.

* *In line 6,* we take the input as `number`.

* *From lines 7 to 11,* we initialize a `for` loop, where we give conditions to run the loop till the number is not equal to `0`. We store the value in the `sum` variable.

* *In line 12,* we print the output stored in the variable `sum`.

In this way, we can use loops to reverse a number in C++.

How to display numbers in reverse order in C++

Use a loop in C++ to print numbers in reverse by iterating until the number is zero.