How to find a union of two arrays in C++

#include <iostream>
using namespace std;
#define sizeOfA 6
#define sizeOfB 8
int findCommonElement(int setA[], int sizeOfSetA, int setB[], int sizeOfSetB)
{
  int commonElemnt =0;
  for(int i=0; i<sizeOfSetA; i++)
  {
      for(int j=0; j<sizeOfSetB; j++)
      {
         if(setA[i]==setB[j])
         {
           commonElemnt++;
         }
      }
  }
}
int *findUnion(int setA[], int sizeOfSetA, int setB[], int sizeOfSetB, int commonElement)
{
  int *unionArray;
  //  Find the size of the new array 
  int sizeOfUnionArray= sizeOfSetA + sizeOfSetB - commonElement; 
  unionArray= new int[sizeOfUnionArray];
  int k=0; // Use this iterator to insert elements in the union array
  for(int i=0; i<sizeOfSetA; i++)
  {
    unionArray[k]=setA[i]; // Copy all the element of the array
    k++;
  }
  for(int i=0; i<sizeOfSetB; i++)
  {
    bool isNotExit= true; // This variable is used to check element is exit or not in unionArray
    for(int j=0; j<sizeOfSetA; j++)
    { 
        if (setA[j]==setB[i])// This condition evaluates if element in both arrays is the same or not and change the isNotExit variable accordingly 
        {
          isNotExit= false;
        }
    }
    if(isNotExit)
    {
      unionArray[k]=setB[i];
      k++;
    }
  }
  return unionArray;
}
int main() 
{
  int * UnionArray;
  // Declare two arrays A and B 
  int A[sizeOfA] = {3,5,7,8,4,9};
  int B[sizeOfB] = {1,2,3,5,9,7,8,6};
  int commonElement=findCommonElement(A,sizeOfA, B,sizeOfB);// Get the number of the common elements of both arrays
  int sizeOfNewArray=sizeOfA+sizeOfB-commonElement;// Calculate the size of the new array
  UnionArray=findUnion(A,sizeOfA,B,sizeOfB, commonElement);
  //Print the array element
  cout<<"{ ";
  for(int i= 0; i<=sizeOfNewArray; i++)
  {
    if(i<sizeOfNewArray)
    {
      cout<<UnionArray[i]<<", ";
    }
    else
    {
      cout<<UnionArray[i]<<" }";
    }
  }
  return 0;
}