Given a matrix, print the sum of the row elements in the matrix.

For example, consider the matrix below.

```
[1, 2, 3]
[4, 5, 6]
[7, 8, 9]
```

The row sum of the matrix above is as follows.

```
6
15
24
```

- The first row in the output, (
`6`

) indicates the sum of the elements of the first row, i.e.,`1`

,`2`

, and`3`

. - The second row in the output, (
`15`

) indicates the sum of the elements of the second row, i.e.,`4`

,`5`

, and`6`

. - The third row in the output, (
`24`

) indicates the sum of the elements of the third row, i.e.,`7`

,`8`

, and`9`

.

- Create an array of size equal to the number of rows. This array is used to store the row sum of every row. Let the array be
`rowSum`

. - Iterate through every row of the matrix and execute the following:
- Initialize a sum variable to zero.
- Loop through all the elements in the row.
- Add every element to the sum variable.

- Add the sum variable to the
`rowSum`

array defined in Step 1 of the algorithm.

- Return the
`rowSum`

array.

- Time complexity - O(N*N)
- Space complexity - O(N)

import java.util.Arrays;public class Main{private static int[] printRowSum(int[][] matrix){int numRows = matrix.length;int numCols = matrix[0].length;int[] rowSum = new int[numRows];for(int i = 0; i < numRows; i++){int sum = 0;for(int j = 0; j < numCols; j++) sum += matrix[i][j];rowSum[i] = sum;}return rowSum;}private static void printMatrix(int[][] matrix){for (int[] row : matrix)System.out.println(Arrays.toString(row));}public static void main(String[] args){int matrix[][] = {{1, 2, 3},{4, 5, 6},{7, 8 , 9}};printMatrix(matrix);System.out.println("The row sum of the above matrix is as follows:");int[] rowSum = printRowSum(matrix);for(int i: rowSum)System.out.println(i);}}

Row Sum of matrix

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