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# How to print alternate elements of an array in Java

Gutha Vamsi Krishna

### Problem statement

You are given an array of size N. You need to print elements for the given array in an alternate order, starting from index 0.

### Example

Input:

• arr = {11,12,13,14}

Output:

• 11 13

#### Explanation

Since we need to start from index 0, we print 11, skip 12, and print 13.

### Solution

• Initialize the array arr with input numbers as 11, 12, 13, 14, 15.

• Find array length n, with length property on the array.

• Use the for loop to traverse the array.

• Start with index 0, go until the last element, and increment index by 2 every time to skip alternate elements.

• Print element.

When the loop ends, we will have printed all the alternate elements in the array.

### Code

class Solution {
public static void main( String args[] ) {
//initialize array
int[] arr = {11, 12, 13, 14, 15};

//array length
int n = arr.length;

// loop through the array and increment by 2
for(int i=0; i<n; i = i+2){
//print element
System.out.println(arr[i]);
}
}
}

### Time and space complexity

This solution takes $O(n)$ time complexity, as we traverse elements in the array once.

The solution then takes $O(1)$ space complexity, as we are not taking extra space to solve this problem aside from the input array.

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Gutha Vamsi Krishna
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