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How to resolve the "storage size of variable isn't known" error
Educative Answers TeamTake a look at the code in C below that defines struct xyx and initializes an object of that struct:
#include <stdio.h>
struct xyx {
int x;
int y;
};
int main(void)
{
struct xyz a;
a.x = 100;
printf("%d\n", a.x);
return 0;
}Executing the code above gives the error main.c:13:16: storage size of ‘a’ isn’t known.
Have a look at the code again!
In our
main, we have created the object a of struct typexyz; however, our struct declaration above had the namexyx.
The compiler is unable to identify the amount of space that needs to be allocated to x because there is no pre-defined or user-defined struct xyz; hence, it gives the error that the storage size of a is not known.
The solution is pretty simple, xyz just needs to be changed to xyx. Take a look at the working code below:
#include <stdio.h>
struct xyx {
int x;
int y;
char c;
char str[20];
int arr[2];
};
int main(void)
{
struct xyx a;
a.x = 100;
printf("%d\n", a.x);
return 0;
}RELATED TAGS
error
storage
size
variable
unknown
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