**`printf`** (print formatted) in C, writes out a cstring to stdout (standard output). The provided cstring may contain format specifiers( beginning with `%` in the cstring). 

If there are format specifiers, those are replaced with their respective arguments that follow the *cstring* to the `printf` call. These format specifiers may also contain its length, precision, and other flags.

# Syntax

``` cpp
 int printf (const char* c-string, ...);
```
- **Return Value**: If the function successfully executes, it returns the total number of characters written to the standard output. If an error occurs, a negative number is returned.

- **Arguments**: `c-string` is the string passed to the function. There can be additional arguments following `c-string`, if there exist format specifiers in the `c-string`, as discussed above.

<br>

# Format Specifer
The format specifier follows the following prototype:

``` css
 %[flags][width][.precision][length]specifier 
```

/* Example for printf() */
#include <stdio.h>

int main(){
   printf ("Integers: %i %u \n", -3456, 3456);
   printf ("Characters: %c %c \n", 'z', 80);
   printf ("Decimals: %d %ld\n", 1997, 32000L);
   printf ("Some different radices: %d %x %o %#x %#o \n", 100, 100, 100, 100, 100);
   printf ("floats: %4.2f %+.0e %E \n", 3.14159, 3.14159, 3.14159);
   printf ("Preceding with empty spaces: %10d \n", 1997);
   printf ("Preceding with zeros: %010d \n", 1997);
   printf ("Width: %*d \n", 15, 140);
   printf ("%s \n", "Educative");
   return 0;
}

How to use printf in C

printf in C outputs a formatted cstring to stdout, replacing format specifiers (%) with respective arguments.

How to use printf in C

Syntax

Format Specifer

Code