How to use the any_of() function in C++
The any_of() function in C++ helps to determine if any of the elements in an array in the specified range satisfy the condition or not. This function is available in the <algorithm.h> header file.
Parameters
The any_of() function accepts the following parameters:
-
first: This is an iterator that points to the first index of the array or vector where we want to perform this check. -
last: This is an iterator that points to the last index of the array or vector where we want to perform this check. -
condition: This is an unary function that accepts one element of the same type as elements you have in the array or vector. This unary function returns a Boolean value that indicates whether the condition issatisfied returns true not returns false
Return
The any_of() function returns a Boolean value true if any of the elements present in the array or vector in the specified range satisfy the condition; otherwise, it returns false.
Code
Let’s look at the code now.
#include <iostream>#include <vector>#include <algorithm>using namespace std;bool IsAnyOdd(int i){return (i % 2 == 1);}int main() {vector<int> vec = {2,4,6,8,10,12,15,18,20};if (any_of(vec.begin(), vec.end(), IsAnyOdd))cout << "At least one number is odd.";elsecout << "All the elements are even.";return 0;}
Explanation
- From lines 1 to 3, we import the required header files.
- In line 6, we create our unary function that will return
trueif the number is odd; otherwise, it will returnfalse. - In line 11, we create a vector of integers.
- In line 13, we call the
any_of()function and pass the required parameters. - Then, in line 14, we print if any of the elements is odd. Otherwise, we print in line 16 that all the elements are even.
