The **`compareTo()` method** of the `Byte` class in Java can be used to compare one `Byte` object to another `Byte` object. 

>The `Byte` class wraps the `byte` type in an object. 

>The **`byte` primitive data type** is an $8$-bit signed two's complement integer that has a minimum value of $-128$ and a maximum value of $127$ (inclusive). 

# 
#  Syntax 

The syntax of the `compareTo()` method is as follows:

```java
public int compareTo(Byte b);
```

## Return value

The `compareTo()` method returns one of the following: 

* If the specified `Byte` object is the same as the object passed as an argument, `compareTo()` returns $0$.

* If the specified `Byte` object is numerically greater than the object passed as an argument, `compareTo()` returns a positive integer.

* If the specified `Byte` object is numerically less than the object passed as an argument, `compareTo()` returns a negative integer.

##
## Code

The code below uses the `compareTo()` method to compare `Byte` objects. 

class ByteCompareToExample {
    public static void main( String args[] ) {
        Byte val1 = 10;

        Byte val2 = 10;
        System.out.println("10, 10 : " + val1.compareTo(val2));

        val2 = 11;
        System.out.println("10, 11 : " + val1.compareTo(val2));

        val2 = 9;
        System.out.println("10, 9 : " + val1.compareTo(val2));
    }
}


#   
## Explanation 

In the code above:

* In line $3$, we create a `Byte` object variable with the name `val1` and value $10$.

* In lines $5$ and $6$, we create another Byte object `val2` with value $10$.  We call the `compareTo()` method on the `val1` object with `val2` as an argument. We get $0$ as a result because the values are equal.

* In lines 8 and 9, we change the value of `val2` to `11` and call the `compareTo()` method on the `val1` object with `val2` as an argument. We get $-1$ as a result because `val1` is less than `val2`.

* In lines $11$ and $12$, we change the value of `val2` to $9$ and call the `compareTo()` method on the `val1` object with `val2` as an argument. We get $1$ as a result because `val1` is greater than `val2`.

What is the Byte.compareTo() method in Java?

The `compareTo()` method in the Byte class compares Byte objects, returning 0 if equal, positive if greater, and negative if less.