#       
## Overview
The **`numpy.hypot()` function** in Python is used to compute the hypotenuse of a given right-angled triangle's sides. The **hypotenuse** is opposite and adjacent to the other two sides of the triangle.

## Diagrammatically 




## Mathematically


numpy.hypot() = sqrt[($opposite ^{2}$) + ($Adjacent^{2}$)]

## Syntax
```
numpy.hypot(x1, x2 /, out=None, *, where=True)
```
## Parameters 
The `numpy.hypot()` function takes the following parameter values:
* **`x1`** and **`x2`**: These represent the legs of the triangle, that is, the opposite and adjacent sides of the triangle. These two values are required for the function to work.
* **`out`**: This represents a location where the result is stored. This is an optional parameter value.
* **`where`**: This is the condition over which the input is being broadcast. At a given location where this condition is `True`, the resulting array will be set to the ufunc result. Otherwise, the resulting array will retain its original value. This is also an optional parameter value.
* **`**kwargs`**: This represents the other keyword arguments.
## Return type
The `numpy.hypot()` function returns the hypotenuse of the given triangle(s).
## Code example

import numpy as np

# creating an array having the legs of triangles
x1 = np.array([4, 5])
x2 = np.array([3, 12])

# taking the arcsin element-wise
myarray = np.hypot(x1, x2)

print(myarray)

## Code explanation 
* **Line 1**: We import the `numpy` module.
* **Lines 4–5**: We create the arrays `x1` and `x2`, which contain the legs of triangles.
* **Line 8**: We implement the `numpy.hypot()` function on the arrays we created. We assign the result to a variable called `myarray`.
* **Line 10**: We print the variable `myarray` to the console.

In the example above, one of the given triangles has its legs (opposite and adjacent sides) as `4` and `3`.

Mathematically:

numpy.hypot(4, 3) = sqrt[($4^{2}$) + ($3^{2}$)] = sqrt(16 + 9) = sqrt(25) = 5.





What is the numpy.hypot() function in Python?

Computes the hypotenuse of right-angled triangle sides using $ \text{sqrt}(x1^2 + x2^2) $.