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Solution Review: Right Rotate an Array by One

Solution Review: Right Rotate an Array by One

This review provides a detailed analysis that helps solve the "Right Rotate an Array by One" challenge.

Solution #

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fn rotate_array(arr: &mut[i32]) -> &[i32]{
    let last_element = arr[arr.len()-1];
    for x in (1..arr.len()).rev(){
        arr[x] = arr[x-1];
    }
    arr[0] = last_element;
    arr
}

Explanation

You iterated over the whole array and stored the next element of the array at the previous index. Lastly, you append the last element arr[arr.len()-1]to the 0 ...

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