You are given an input string, s, and a pattern string, p. Your task is to implement regular expression matching between s and p, where the pattern may include the special characters '.' and '*':
'.' matches any single character.
'*' matches zero or more occurrences of the preceding character.
The match must cover the entire input string, not just part of it.
Constraints:
s.length
p.length
s contains only lowercase English letters.
p contains only lowercase English letters, '.', and '*'.
It is guaranteed that for each appearance of the character '*', there will be a previous valid character to match.
One of the first ideas that comes to mind to solve the regular expression matching problem is to compare the string s and the pattern p character by character. At each step, we could check if the current characters match, and when we encounter special symbols like '.' or '*', we could try to handle them separately. However, this naive approach quickly becomes complicated because the '*' operator can represent zero or more repetitions of the previous ...
You are given an input string, s, and a pattern string, p. Your task is to implement regular expression matching between s and p, where the pattern may include the special characters '.' and '*':
'.' matches any single character.
'*' matches zero or more occurrences of the preceding character.
The match must cover the entire input string, not just part of it.
Constraints:
s.length
p.length
s contains only lowercase English letters.
p contains only lowercase English letters, '.', and '*'.
It is guaranteed that for each appearance of the character '*', there will be a previous valid character to match.
One of the first ideas that comes to mind to solve the regular expression matching problem is to compare the string s and the pattern p character by character. At each step, we could check if the current characters match, and when we encounter special symbols like '.' or '*', we could try to handle them separately. However, this naive approach quickly becomes complicated because the '*' operator can represent zero or more repetitions of the previous ...