You’re given an array of integers called nums. Your task is to count how many triplets of indexes (i, j, k) satisfy the condition nums[i] & nums[j] & nums[k] == 0, where & is the bitwise AND operator and ijk nums.length.
Constraints:
nums.length
nums[i]
The essence of this solution lies in breaking the problem into two phases. First, precompute and count all possible pairwise bitwise AND results of the array elements, storing their frequencies in a hash map. Then, check how many of these precomputed results produce zero for each number in the array when ANDed with that number. If they do, add their frequency to the total count, since each matching pair combined with the current number forms a valid ...
You’re given an array of integers called nums. Your task is to count how many triplets of indexes (i, j, k) satisfy the condition nums[i] & nums[j] & nums[k] == 0, where & is the bitwise AND operator and ijk nums.length.
Constraints:
nums.length
nums[i]
The essence of this solution lies in breaking the problem into two phases. First, precompute and count all possible pairwise bitwise AND results of the array elements, storing their frequencies in a hash map. Then, check how many of these precomputed results produce zero for each number in the array when ANDed with that number. If they do, add their frequency to the total count, since each matching pair combined with the current number forms a valid ...