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The **RSA algorithm** is an asymmetric cryptography algorithm; this means that it uses a *public* key and a *private* key (i.e two different, mathematically linked keys). As their names suggest, a public key is shared publicly, while a private key is secret and must not be shared with anyone.

The RSA algorithm is named after those who invented it in 1978: Ron Rivest, Adi Shamir, and Leonard Adleman.

The following illustration highlights how asymmetric cryptography works:

The RSA algorithm ensures that the keys, in the above illustration, are as secure as possible. The following steps highlight how it works:

- Select two large prime numbers, $x$ and $y$. The prime numbers need to be large so that they will be difficult for someone to figure out.
- Calculate $n = x * y$.
- Calculate the
function; $\phi(n) = (x-1)(y-1)$.**totient** - Select an integer $e$, such that $e$ is
to $\phi(n)$ and $1 < e < \phi(n)$. The pair of numbers $(n,e)$ makes up the public key.**co-prime**

Note:Two integers are co-prime if the only positive integer that divides them is 1.

- Calculate $d$ such that $e.d = 1$ $mod$ $\phi(n)$.

$d$ can be found using the * extended euclidean algorithm*. The pair $(n,d)$ makes up the private key.

Given a plaintext $P$, represented as a number, the ciphertext $C$ is calculated as:

$C = P^{e}$ $mod$ $n$.

Using the private key $(n,d)$, the plaintext can be found using:

$P = C^{d}$ $mod$ $n$.

Consider an example of the RSA algorithm through the following pseudocode:

```
int x = 61, int y = 53;
int n = x * y;
// n = 3233.
// compute the totient, phi
int phi = (x-1)*(y-1);
// phi = 3120.
int e = findCoprime(phi);
// find an 'e' which is > 1 and is a co-prime of phi.
// e = 17 satisfies the current values.
// Using the extended euclidean algorithm, find 'd' which satisfies
// this equation:
d = (1 mod (phi))/e;
// d = 2753 for the example values.
public_key = (e=17, n=3233);
private_key = (d=2753, n=3233);
// Given the plaintext P=123, the ciphertext C is :
C = (123^17) % 3233 = 855;
// To decrypt the cypher text C:
P = (855^2753) % 3233 = 123;
```

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