Solution: Rearrange Sorted Array in Max/Min Form

Explore how to rearrange a sorted array into a max/min alternating pattern using JavaScript. Learn two distinct approaches—creating a new array and an in-place method using modulus and pointers—and understand their time and space complexities. This lesson equips you with efficient array manipulation techniques for coding interviews.

We'll cover the following...

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Solution 1: Create a new array
- Complexity analysis
Solution 2: Use modulus (%) and two pointers
- Complexity analysis

Statement

We're given a sorted array, nums, containing positive integers only. We have to rearrange the array so that when returned, the $0^{th}$ index of the array will have the largest number, the $1^{st}$ index will have the smallest number, the $2^{nd}$ index will have the second largest number, the $3^{rd}$ index will have the second smallest number, and so on.

In the end, we’ll have the largest remaining numbers in descending order and the smallest in ascending order at even and odd positions, respectively.

Constraints:

$0 \leq$ nums.length $\leq 10^3$ ...

1.Introduction to Complexity Measures

2.Introduction to Arrays

3.Introduction to Linked Lists

4.Introduction to Stack/Queues

5.Introduction to Graphs

6.Introduction to Trees

7.Trie

8.Introduction to Heap

9.Introduction to Hashing

10.Summary of Data Structures

Mock Interview

Solution: Rearrange Sorted Array in Max/Min Form

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