# Solution: Maximum Sublist

Let's solve the Maximum Sublist problem.

We'll cover the following

## Statement

Given an unsorted list nums, find the sum of the maximum sum sublist. The maximum sum sublist is a list of contiguous elements in nums for which the sum of the elements is maximum.

Constraints:

• $1 \leq$ nums.length $\leq 10^3$

• $-10^4 \leq$ nums[i] $\leq 10^4$

## Solution

The maximum sublist sum problem inherently involves examining various sublists to check if their sum is maximized, and the most convenient and efficient way to do this is using dynamic programming. The key idea is to efficiently find the maximum sublist ending at any position based on the maximum sublist ending at the previous position.

In the context of this problem, we’ll use Kadane’s algorithm. It uses the bottom-up approach of dynamic programming to solve subproblems iteratively, starting from the smallest subproblems and building up toward the larger problem. The subproblem here is to find the maximum sublist sum that ends at a specific index i. We need to calculate this for every index i in the array. The base case is the first element of the array, where both the current sublist sum and maximum sublist sum are initialized with the first element’s value. This is the starting point for solving the subproblems. We reuse the previously computed maximum sublist sum at each step to find the solution for the current subproblem.

The steps of the algorithm are given below:

• Initialize a curr_max variable to keep track of the maximum sum of the current list index and another global_max variable to keep track of the largest sum seen so far. Both variables will be initialized with the first element of nums.

• Traverse the list from the second element until the end of the list is reached.

• While traversing, if curr_max is less than 0, assign it the element at the current index. Otherwise, add the element at the current index to curr_max.

• Next, if global_max is less than curr_max, reassign it to curr_max.

Let’s look at the illustration below to better understand the solution:

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