Solution: Middle of the Linked List
Let’s solve the Middle of the Linked List problem.
We'll cover the following
Statement
Given the head
of a singly linked list, return the middle node of the linked list.
If there are two middle nodes, return the second middle node. This happens when the length of the list is even, and the second middle node occurs at $\frac {length}{2}$. Otherwise, if the length of the list is odd, the middle node occurs at $\frac {length}{2}+1$.
Constraints:
Let n
be the number of nodes in a linked list.
 $1 \leq$
n
$\leq 100$  $1 \leq$
node.data
$\leq 100$ head
$\neq$ NULL
Solution 1: Brute force
We can first determine the length of the linked list; based on the length, we can then calculate the position of the middle node. If the length is even, the middle position will be half the length of the list. If the length is odd, the middle position will be half the length plus one.
The steps of the algorithm are given below:

Implement a length function to determine the total number of nodes in the linked list. Iterate through the list, starting from the
head
, and increment a counter for each node encountered until reaching the end of the list. 
Initialize the
node
to the head of the linked list. 
Set
mid
to half of the length plus one. 
Traverse the linked list using a loop that runs
mid  1
times:a. In each iteration, advance the
node
to the next node. 
After the loop, the
node
points to the middle node of the linked list. Then, return thenode
.
Let’s look at the code for this solution below:
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