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Puzzle 16 Explanation: Channel Capacity

Explore how buffered channels operate in Go by sending and receiving values, handling closed channels, and using the comma ok pattern to distinguish valid data from zero values.

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Try it yourself

Try executing the code below to see the result.

Go (1.16.5)
package main
import (
	"fmt"
)
func main() {
	ch := make(chan int, 2)
	ch <- 1
	ch <- 2
	<-ch
	close(ch)
	a := <-ch
	b := <-ch
	fmt.Println(a, b)
}

Explanation

The ch channel is a buffered channel with a capacity of 2 (we can check this ...