Discussion: More Simple
Execute the code to understand the output and gain insights into simplifying a fraction using C.
We'll cover the following...
We'll cover the following...
Run the code
Now, it's time to execute the code and observe the output.
#include <stdio.h>
int main()
{
int n, d, larger, smaller, diff;
printf("Enter a fraction (nn/nn): ");
scanf("%d/%d", &n, &d);
// Check if the denominator is zero
if (d == 0)
{
printf("Error: Denominator cannot be zero.\n");
return 1; // Exit the program with an error code
}
printf("%d/%d = ", n, d);
larger = n > d ? n : d;
smaller = n < d ? n : d;
diff = larger - smaller;
while (diff != larger)
{
larger = smaller > diff ? smaller : diff;
smaller = smaller == larger ? diff : smaller;
diff = larger - smaller;
}
if (diff > 1)
printf("%d/%d\n", n / diff, d / diff);
else
printf("%d/%d\n", n, d);
return 0;
}
C code for the given puzzle
Understanding the output
The code requires that you input two integers in the form of a fraction, such as 21/63. Here's the output:
Enter a fraction (nn/nn):21/63 = 1/3
Code output
The fraction is reduced—simplified—if it can be. When the fraction can’t be simplified, the original fraction is returned as output.
Explanation
Computers are ...