TarballFiber.tar.gz

raceFlag

server side

user input

server side-copy

serverJob

Go (also known as Golang) is one of the most popular languages today and is a key part of many enterprise tech stacks. Because Go's memory management architecture makes concurrency easier, many developers prefer it over traditional languages.

In this course, you will learn the core constructs and techniques of Go as well as advanced concepts of the language. In particular, you’ll learn how to program efficiently by becoming aware of the pitfalls and patterns that are commonly encountered in Go and by building your own applications.

Once you’ve completed this course, you will be able to write concurrent programs and improve the performance of existing ones, thus creating a more robust experience for everyone. Concurrency is in high demand today since it enables developers to reduce execution time of applications significantly, and Golang provides a very rich support for achieving this.

Concurrency in Go

What will be the output of the program mentioned below?

```go
package main

import "fmt"

func main() {
	var ch chan string
	var count int

	go func() {
		ch <- "Hi"
	}()

	go func() {
		count++
		close(ch)
	}()

	<-ch
	fmt.Println(count)
}
```

What will be the output of the program mentioned below?
<pre><code class="language-go">package main

import &quot;fmt&quot;

func main() {
	var ch chan string
	var count int

	go func() {
		ch &lt;- &quot;Hi&quot;
	}()

	go func() {
		count++
		close(ch)
	}()

	&lt;-ch
	fmt.Println(count)
}
</code></pre>

```go
for {
 val, ok := <-ch
 if ok {
 break
 }
 fmt.Println(val)
}
```

```go
for {
 val, ok := <-ch
 if !ok {
 break
 }
 fmt.Println(val)
}
```

```go
for {
 val, !ok := <-ch
 if ok {
 break
 }
 fmt.Println(val)
}
```

Select the code equivalent to the following:

```go 
for val := range <-ch {
 fmt.Println(val)
}
```

Select the code equivalent to the following:
<pre><code class="language-go">for val := range &lt;-ch {
 fmt.Println(val)
}
</code></pre>

The code will throw a compile-time error.


The main goroutine will exit before `printValue` executes.

The program will print `Value inside the channel is 2.`


What will be the output of the following code snippet?

```go
package main

import (
	"fmt"
	"sync"
)

func printValue(goChannel <-chan int) {
	fmt.Println("Value inside the channel is ", <-goChannel)
	goChannel <- 1
}

func main() {
	goChannel := make(chan int)
	go printValue(goChannel)
	goChannel <- 2
}
```

What will be the output of the following code snippet?
<pre><code class="language-go">package main

import (
	&quot;fmt&quot;
	&quot;sync&quot;
)

func printValue(goChannel &lt;-chan int) {
	fmt.Println(&quot;Value inside the channel is &quot;, &lt;-goChannel)
	goChannel &lt;- 1
}

func main() {
	goChannel := make(chan int)
	go printValue(goChannel)
	goChannel &lt;- 2
}
</code></pre>

Quiz yourself on the concepts of channels.


Quiz

Quiz yourself on the concepts of channels.

Introduction to Concurrency

General Concepts

Sync

Goroutines

Channels

Implementing Concurrency Patterns

Conclusion

Quiz