Python 3: From Beginner to Advanced/

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Solution Review: Finding the Customer With the Most Purchases

Solution Review: Finding the Customer With the Most Purchases

This review explains the solution for the "most purchases'"problem.

We'll cover the following...

Solution

Python 3.5
def most_purchases(groceries):
    most_purchase_customer = None
    max_purchases_sum = 0
    
    for key in groceries:
        curr_sum = sum(groceries[key])
        if curr_sum > max_purchases_sum:
            max_purchases_sum = curr_sum
            most_purchase_customer = key
    return (most_purchase_customer, max_purchases_sum)
groceries = {
    "James": [10, 2, 5, 7, 9, 4, 6],
    "Tom": [1, 12, 3, 0, 1, 2, 5],
    "Sam": [9, 5, 4, 3, 2, 1, 3], 
}
customer_results = most_purchases(groceries)
print(customer_results)

Explanation

The first thing we need to do is create two new variables: most_purchase_customer and max_purchases_sum at lines 2 to 3 respectively. These will be used to store the name of the customer who made ...