Solution: Flow Lifecycle Functions
See the solution to the challenge just presented.
We'll cover the following...
We'll cover the following...
Solution
The solution to the challenge we just solved is as follows.
suspend fun main() { flowOf("A", "B") .onEach { delay(2000) } .onStart { println("Started") } .collect { println(it) } }
Complete code of the solution
Explanation
Here is a line–by–line ...