Solution: Find Duplicates in an Array with No Repetition
Explore various approaches to solving the challenge of efficiently finding duplicates in an array.
Solution 1: Brute force
Explanation
The solution takes one element from the array, compares it with every other element (starting from i + 1), and checks if they both are equal. If they are, it adds it to the resultant array if the number is not present already.
Time complexity
The array is iterated once for each element present, so the time complexity is in ...