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Solution: Minimum Remove to Make Valid Parentheses

Understand how to use a stack to remove the minimum number of invalid parentheses from a string. Learn to identify matching and unmatched parentheses, apply the Last In First Out method to maintain valid pairs, and return a corrected string with balanced parentheses. This lesson helps you grasp the approach's time and space complexity, making it easier to solve similar stack-based problems.

Statement

Given a string, s, that may have matchedEach opening parenthesis, (, has a closing parenthesis, ), for it. and unmatchedThere is no corresponding closing parenthesis, ), for an opening parenthesis, (. parentheses, remove the minimum number of parentheses so that the resulting string represents a valid parenthesization. For example, the string “a(b)” represents a valid parenthesization while the string “a(b” doesn’t, since the opening parenthesis doesn’t have any corresponding closing parenthesis.

Constraints:

  • 11 \leq s.length 103\leq 10^3
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