Solution: Insert into a Sorted Circular Linked List
Explore how to insert a given value into a sorted circular linked list while maintaining its sorted order and circular structure. This lesson helps you understand handling edge cases like inserting at wrap-around points or when all nodes have identical values. You will learn to use two pointers to find the correct insertion spot efficiently with linear time and constant space complexity.
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Statement
You’re given a reference to a node, head, in a circular linked list, where the values are sorted in non-decreasing order. The list is circular, so the last node points to the first node. However, the head can be any node in the list—it is not guaranteed to be the node with the smallest value.
Your task is to insert a new value, insertVal, into the list so that it remains sorted and circular after the insertion.
You can choose any of the multiple valid spots where the value can be inserted while maintaining the sort order.
If the list is empty (i.e., the given node is NULL), create a new circular list with a single node containing
insertVal, and return that node.Otherwise, return the
headnode after insertion.
Constraints:
The number of nodes in the list is in the range
. Node.val,insertVal...