Solution: Jewels and Stones
Explore how to solve the Jewels and Stones problem by implementing hash maps in C++. Learn to count characters in one string that appear in another with efficient membership checks and case-sensitive matching.
We'll cover the following...
We'll cover the following...
Statement
You are given two strings, jewels and stones. Each character in jewels represents a stone type that is a jewel, and each character in stones represents a stone you have. Count how many characters in stones belong to the set of characters in jewels.
Note: Matching is case-sensitive, so
'a'and'A'are different types of stones.
Constraints:
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