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Grokking the Coding Interview Patterns in Go

Solution: Minimum Remove to Make Valid Parentheses

Understand how to use stacks to identify and remove the minimum invalid parentheses from a string, ensuring valid parenthesization. This lesson covers implementing a stack-based solution with time and space complexity analysis, enabling you to handle related coding interview problems confidently.

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Statement

Given a string, s, that may have matchedEach opening parenthesis, (, has a closing parenthesis, ), for it. and unmatchedThere is no corresponding closing parenthesis, ), for an opening parenthesis, (. parentheses, remove the minimum number of parentheses so that the resulting string represents a valid parenthesization. For example, the string “a(b)” represents a valid parenthesization while the string “a(b” doesn’t, since the opening parenthesis doesn’t have any corresponding closing parenthesis.

Constraints:

  • 1≤1 \leq s.length ≤103\leq 10^3
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