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Solution: Word Break

Explore how to solve the Word Break problem using dynamic programming techniques in Go. Learn to build a lookup table that helps efficiently check if a string can be segmented into valid dictionary words, improving over naive recursion by reducing redundant checks. Understand the tradeoffs in time complexity and how to implement the solution effectively.

Statement

Given a string, s, and a dictionary of strings, wordDict, check if s can be segmented into a space-separated sequence of one or more dictionary words. If yes, return TRUE; else, return FALSE.

Note: The same word in the dictionary may be used multiple times.

Constraints:

  • 11 \leq s.length 250\leq 250

  • 11 \leq wordDict.length 1000\leq 1000

  • 11 \leq wordDict[i].length 20\leq 20

  • s and wordDict[i] consist of only lowercase English letters.

  • All the strings of wordDict are unique.

Solution

So far, you’ve probably brainstormed some approaches and have an idea of how to solve this problem. Let’s explore some of these approaches and figure out which one to follow ...