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Shortest Bridge

Explore how to find the minimum number of water cells to flip in a grid to connect two islands. This lesson helps you understand adjacency, grid traversal, and optimize your approach using efficient algorithms, reinforcing key coding interview patterns.

Statement

We are given an n×nn×n binary matrix grid containing 0s and 1s. Each cell in the grid represents either land or water. A cell with a value of 1 represents land, while a cell with a value of 0 represents water. A group of adjacent cells with a value of 1 constitutes an island. Two cells are considered adjacent if one is above, below, to the left, or to the right of the other. Our task is to return the smallest number of 0s we must flip to connect the two islands.

Note: We may assume all four edges of the grid are surrounded by water.

Constraints:

  • 22 \leq n \leq 2020

  • n==n == grid.length ==== grid[i].length.

  • grid[i][j] is either 0 or 1.

  • There are exactly two islands in the grid.

Example

Understand the problem

Let’s take a moment to make sure you’ve correctly understood the problem. The quiz below helps us to check if you’re solving the correct problem:

Shortest Bridge

1.

What is the smallest number of 0s we must flip to connect the two islands if the following matrix is given?

[[0,1,0,0,0]
[0,1,0,0,0]
[1,1,0,0,1]
[0,0,0,0,1]
[0,0,0,0,1]] 
A.

1

B.

2

C.

3

D.

None of the above


1 / 2

Try it yourself

Implement your solution in the following coding playground:

The optimal solution to this problem runs in O(n2) time and takes O(n2) space.

Java
usercode > ShortestBridge.java
import java.util.*;
public class ShortestBridge{
public static int shortestBridge(int[][] grid){
// Replace this placeholder return statement with your code
return -1;
}
}
Shortest Bridge