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Grokking the Coding Interview Patterns

Solution: Minimum Remove to Make Valid Parentheses

Understand how to traverse a string and apply stack operations to identify and remove unmatched parentheses, resulting in a valid parenthesization. Explore how this approach ensures optimal time and space complexity for solving parentheses validation problems.

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Statement

Given a string, s, that may have matchedEach opening parenthesis, (, has a closing parenthesis, ), for it. and unmatchedThere is no corresponding closing parenthesis, ), for an opening parenthesis, (. parentheses, remove the minimum number of parentheses so that the resulting string represents a valid parenthesization. For example, the string “a(b)” represents a valid parenthesization while the string “a(b” doesn’t, since the opening parenthesis doesn’t have any corresponding closing parenthesis.

Constraints:

  • 1≤1 \leq s.length
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