Solution: Find the Longest Substring Having Vowels in Even Counts
Understand how to solve the problem of finding the longest substring with vowels that appear an even number of times by applying bitwise XOR operations. Learn to represent each vowel as a bit, toggle counts efficiently, and track substring states to identify valid segments, optimizing for time and space complexity.
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Statement
Given the string s, return the length of the longest
Constraints:
s.lengthscontains only lowercase English letters.
Solution
It’s important to note that we only need to know whether each vowel appears an even or odd number of times in any substring—we don’t need the exact counts. This is where bitwise operations can help. In bitwise terms, we use XOR on its bits to check if a value occurs an even or odd number of times (its parity). If the result of XOR is 1, the value has occurred an odd number of times; if it’s 0, it’s even. We’ll apply this idea to the characters in the input string: each vowel is represented by a bit, and as we process each character, we’ll use XOR with a fixed-size bitmask to track whether it has an even or odd count. ...