Solution: Insert into a Sorted Circular Linked List
Explore how to insert a new value into a sorted circular linked list where the head can be any node. Understand the use of two pointers to find the correct position to keep the list sorted and circular, handle edge cases like the turning point between max and min values, and manage scenarios where all nodes have the same value. This lesson teaches efficient in-place insertion with O(n) time and O(1) space complexity.
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Statement
You’re given a reference to a node, head, in a circular linked list, where the values are sorted in non-decreasing order. The list is circular, so the last node points to the first node. However, the head can be any node in the list—it is not guaranteed to be the node with the smallest value.
Your task is to insert a new value, insertVal, into the list so that it remains sorted and circular after the insertion.
You can choose any of the multiple valid spots where the value can be inserted while maintaining the sort order.
If the list is empty (i.e., the given node is NULL), create a new circular list with a single node containing
insertVal, and return that node.Otherwise, return the
headnode after insertion.
Constraints:
The number of nodes in the list is in the range
. Node.val,insertVal...