Solution Review: Count with Dictionary
The solution to the 'Count with Dictionary' challenge.
We'll cover the following
from collections import defaultdictfrom collections import OrderedDictdef count_letters(message):d = defaultdict(int) # Making dictionary with intfor letter in message:d[letter] += 1 # Adding 1 with every repetition# Sorting on the basis of valuesreturn OrderedDict(sorted(d.items(), key = lambda t:t[1]))print(count_letters('Welcome to Educative'))
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