Solution: Insert into a Sorted Circular Linked List
Understand how to perform an in-place insertion in a sorted circular linked list with non-decreasing values. This lesson guides you through handling edge cases where the head may not be the smallest node, using two-pointer traversal to locate the correct insertion point. You'll learn to maintain both the circular nature and sorted order of the list efficiently while dealing with scenarios such as empty lists, uniform values, and insertion at the rotation point.
We'll cover the following...
Statement
You’re given a reference to a node, head, in a circular linked list, where the values are sorted in non-decreasing order. The list is circular, so the last node points to the first node. However, the head can be any node in the list—it is not guaranteed to be the node with the smallest value.
Your task is to insert a new value, insertVal, into the list so that it remains sorted and circular after the insertion.
You can choose any of the multiple valid spots where the value can be inserted while maintaining the sort order.
If the list is empty (i.e., the given node is NULL), create a new circular list with a single node containing
insertVal, and return that node.Otherwise, return the
headnode after insertion.
Constraints:
The number of nodes in the list is in the range
. Node.val,insertVal
Solution
The intuition behind this ...