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Solution: Minimum Remove to Make Valid Parentheses

Understand how to use a stack to solve the minimum remove to make valid parentheses problem. This lesson teaches you to identify unmatched parentheses in a string and remove them efficiently in linear time by leveraging last-in, first-out operations.

Statement

Given a string, s, that may have matchedEach opening parenthesis, (, has a closing parenthesis, ), for it. and unmatchedThere is no corresponding closing parenthesis, ), for an opening parenthesis, (. parentheses, remove the minimum number of parentheses so that the resulting string represents a valid parenthesization. For example, the string “a(b)” represents a valid parenthesization while the string “a(b” doesn’t, since the opening parenthesis doesn’t have any corresponding closing parenthesis.

Constraints:

  • 11 \leq s.length
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