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Solution: Count Pairs in Two Arrays

Understand how to count pairs of indices from two arrays where sums from the first exceed sums from the second by using a difference array. Explore sorting and binary search techniques to optimize and reduce time complexity from O(n²) to O(n log n). Learn to implement this algorithm with clear steps and complexity analysis.

Statement

You are given two positive integer arrays, nums1 and nums2, both of length nn. Your task is to count and return the number of pairs of indexes (i,j)(i, j) where:

  • i<ji < j , and

  • nums1[i]+nums1[j]>nums2[i]+nums2[j]\text{nums1}[i] + \text{nums1}[j] > \text{nums2}[i] + \text{nums2}[j]

In simpler terms, the sum of two elements from nums1 must be greater than that of the corresponding elements from nums2.

Constraints:

  • n=n = ...